- Principles of Chemistry I: Honors
Fall 2013, Unique 52195
Lecture Summary, 15 October 2013
After a lot of build-up, we have finally arrived at the
mechanical solution to explain the hydrogen atom. This
is found by solving the Schrodinger equation by finding a
that fits the boundary conditions, just like we did for the
particle-in-a-box. First, we are going to put our system
spherical polar coordinates, because that is the coordinate system
which most succinctly describes a system with the symmetry of a
Thus, instead of have coordinates x,
y, z, we have coordinates r,
theta, and phi
to describe the position of our electron around the nucleus (which
fixed at the origin). Our boundary condition is that the
wavefunction psi goes to
0 as r
goes to 0, which makes sense because we need to explain the system
the condition where the electron is pretty close to the nucleus.
The Schrodinger equation can be solved exactly for the hydrogen atom, and it's actually not that hard, but it is a lot of calculus that is out of the scope of this class. Therefore we will not solve this ourselvs, but simply deal with the outcomes of the solutions, the wavefunction and energy of the hydrogen atom. To solve the Schrodinger equation, it is necessary to break up the solution into a radial part, dependent on r, and an angular part, dependent on theta and phi. This turns out to be really helpful for two reasons: 1) the total energy of the system, E, depends only on r, not on any angle; and 2) this makes our wavefunctions much easier to visualize.
The solutions to the Schrodinger equation give us 3 quantum numbers:
n = 1, 2, 3... principal quantum number
l = 0, 1, 2...n-1 angular momentum quantum number
m = -l, -l+1, -l+2...0...l-2, l-1, l magnetic quantum number
This means that certain quantum numbers are allowed for each value of n. However, the energy of the system depends on n only, so states that have the same n but different l and m are said to be "degenerate."
The wavefunctions that solve the Schrodinger equation for the hydrogen atom are:
psin,l,m(r,theta,phi) = Rn,l(r)Yl,m(theta,phi)
The function R is the radial part of the wavefunction, and Y is the angular part of the wavefunction. R and Y for the first few quantum numbers are tabulated in Table 5.2 in your book.